Solved: PHYSICS Question for NEET

NEET PHYSICSMedium

A police jeep is chasing with a velocity of $45 \text{ km/h}$ a thief in another jeep moving with a velocity of $153 \text{ km/h}$ . Police fire a bullet with a muzzle velocity of $180 \text{ m/s}$ . The velocity with which it will strike the car of the thief is:

150 m/s

27 m/s

450 m/s

250 m/s

Step-by-Step Solution

Convert Velocities to SI Units (m/s): Velocity of Police Jeep ( $v_p$ ) = $45 \text{ km/h} = 45 \times \frac{5}{18} = 12.5 \text{ m/s}$ . Velocity of Thief's Jeep ( $v_t$ ) = $153 \text{ km/h} = 153 \times \frac{5}{18} = 42.5 \text{ m/s}$ .
Effective Velocity of Bullet: Since the bullet is fired from the moving police jeep, its velocity relative to the ground ( $v_{b,g}$ ) is the sum of the muzzle velocity and the jeep's velocity.

$v_{b,g} = \text{Muzzle Velocity} + v_p = 180 + 12.5 = 192.5 \text{ m/s}$ .

Calculate Relative Velocity: The velocity with which the bullet strikes the thief's car is the relative velocity of the bullet with respect to the thief ( $v_{b,t}$ ). Since both are moving in the same direction: $v_{b,t} = v_{b,g} - v_t$ . $v_{b,t} = 192.5 - 42.5 = 150 \text{ m/s}$ .

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