Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

In the given V-T diagram, what is the relation between pressure $P_1$ and $P_2$ ?

$P_2 > P_1$

$P_2 < P_1$

cannot be predicted

$P_2 = P_1$

Analyze the Ideal Gas Equation: The behavior of an ideal gas is governed by the equation $PV = nRT$ .
Analyze the V-T Graph: The diagram plots Volume ( $V$ ) versus Temperature ( $T$ ). Rearranging the ideal gas equation to express $V$ as a function of $T$ (keeping Pressure $P$ constant for each line) gives $V = \left(\frac{nR}{P}\right)T$ . This is the equation of a straight line $y = mx$ passing through the origin.
Slope-Pressure Relationship: The slope of the line ( $m$ ) is equal to $\frac{nR}{P}$ . Since $n$ and $R$ are constants, the slope is inversely proportional to the pressure ( $m \propto \frac{1}{P}$ ). This means a line with a steeper slope (higher $V$ for a given $T$ ) corresponds to a lower pressure.
Conclusion: For the relation $P_2 < P_1$ to be true, the line corresponding to $P_2$ must have a larger slope (be closer to the V-axis) than the line corresponding to $P_1$ . Conversely, the line with the smaller slope represents the higher pressure ( $P_1$ ).

Practice Mode Available

Join thousands of students and practice with AI-generated mock tests.