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NEET PHYSICSMedium

A particle of mass M is situated at the centre of a spherical shell of mass M and radius a. The gravitational potential at a point situated at a/2 distance from the centre will be:

A

-3GM/a

B

-2GM/a

C

-GM/a

D

-4GM/a

Step-by-Step Solution

The gravitational potential at a point is the scalar sum of the potentials due to individual masses. Let the point be PP at a distance r=a/2r = a/2 from the centre.

  1. Potential due to the particle at the centre (V1V_1): The particle behaves as a point mass. At distance r=a/2r = a/2: V1=GMr=GMa/2=2GMaV_1 = -\frac{GM}{r} = -\frac{GM}{a/2} = -\frac{2GM}{a}.
  2. Potential due to the spherical shell (V2V_2): The point PP lies inside the shell (r<ar < a). The gravitational potential inside a spherical shell is constant and equal to the potential at its surface. V2=GMRshell=GMaV_2 = -\frac{GM}{R_{shell}} = -\frac{GM}{a}.
  3. Total Potential (VV): V=V1+V2=(2GMa)+(GMa)=3GMaV = V_1 + V_2 = \left(-\frac{2GM}{a}\right) + \left(-\frac{GM}{a}\right) = -\frac{3GM}{a}.
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