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The magnetic flux linked to a circular coil of radius R is given by: ϕ=2t3+4t2+2t+5\phi = 2t^3 + 4t^2 + 2t + 5 Wb. What is the magnitude of the induced EMF in the coil at t=5t = 5 s?

A

108 V

B

197 V

C

150 V

D

192 V

Step-by-Step Solution

According to Faraday's Law of Induction, the magnitude of the induced electromotive force (ε|\varepsilon|) is equal to the rate of change of magnetic flux (ϕ\phi) with respect to time (tt).

  1. Formula: ε=dϕdt|\varepsilon| = \left| \frac{d\phi}{dt} \right|
  2. Given Flux: ϕ=2t3+4t2+2t+5\phi = 2t^3 + 4t^2 + 2t + 5
  3. Differentiation: dϕdt=ddt(2t3+4t2+2t+5)\frac{d\phi}{dt} = \frac{d}{dt}(2t^3 + 4t^2 + 2t + 5) dϕdt=6t2+8t+2\frac{d\phi}{dt} = 6t^2 + 8t + 2
  4. Calculation at t = 5 s: εt=5=6(5)2+8(5)+2|\varepsilon|_{t=5} = 6(5)^2 + 8(5) + 2 εt=5=6(25)+40+2|\varepsilon|_{t=5} = 6(25) + 40 + 2 εt=5=150+40+2=192 V|\varepsilon|_{t=5} = 150 + 40 + 2 = 192 \text{ V}
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