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NEET PHYSICSEasy

The peak voltage of the AC source is equal to:

A

1/√2 times the rms value of the AC source.

B

the value of voltage supplied to the circuit.

C

the rms value of the AC source.

D

√2 times the rms value of the AC source.

Step-by-Step Solution

According to the sources, the relationship between the root mean square (rms) voltage (VV) and the peak voltage (vmv_m) is defined by the equation V=vm2V = \frac{v_m}{\sqrt{2}} . By rearranging this formula, we find that the peak voltage is equal to 2\sqrt{2} times the rms value (vm=2Vv_m = \sqrt{2} V) . For instance, a household line voltage of 220 V (which is an rms value) has a peak voltage of approximately 311 V (220 V×2220 \text{ V} \times \sqrt{2}) .

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