Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

The work done to raise a mass m from the surface of the earth to a height h, which is equal to the radius of the earth, is:

mgR

2mgR

$\frac{1}{2} mgR$

$\frac{3}{2}mgR$

Step-by-Step Solution

Initial potential energy at earths surface is $U_i = -\frac{GMm}{R}$ Final potential energy at height $h = R$ $U_f = -\frac{GMm}{2R}$ As work done = Change in $PE$ $\therefore W = U_f - U_i$ $\frac{GMm}{2R} = \frac{gR^2 m}{2R} = \frac{mgR}{2} \quad (GM = gR^2)$

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