According to Gauss's Law, the net electric flux $\Phi_E$ through a closed surface depends only on the net charge enclosed ($q$) and the permittivity of free space ($\varepsilon_0$), independent of the size or shape of the surface. Formula: $\Phi_E = \frac{q}{\varepsilon_0}$ Given: $q = 2.0 \, \mu\text{C} = 2.0 \times 10^{-6} \, \text{C}$ $\varepsilon_0 \approx 8.854 \times 10^{-12} \, \text{C}^2 \text{N}^{-1} \text{m}^{-2}$ Calculation: $\Phi_E = \frac{2.0 \times 10^{-6}}{8.854 \times 10^{-12}} \approx 0.2258 \times 10^6 = 2.26 \times 10^5 \, \text{N m}^2 \text{C}^{-1}$. (See NCERT Physics Class 12, Exercise 1.18).