Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

The minimum wavelength of X-rays produced by an electron accelerated through a potential difference of $V$ volts is proportional to

$\sqrt{V}$

$\frac{1}{V}$

$\frac{1}{\sqrt{V}}$

$V^2$

Step-by-Step Solution

The energy of the electron is $eV = \frac{hc}{\lambda_{min}}$ . Therefore, $\lambda_{min} = \frac{hc}{eV}$ . Since $h, c, e$ are constants, $\lambda_{min} \propto \frac{1}{V}$ .

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