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NEET PHYSICSEasy

The energy of the EM wave is of the order of 15 keV15 \text{ keV}. To which part of the spectrum does it belong?

A

X-rays

B

Infrared rays

C

Ultraviolet rays

D

γ\gamma-rays

Step-by-Step Solution

The relationship between energy (EE) and wavelength (λ\lambda) is given by λ=hcE\lambda = \frac{hc}{E}. Using the value hc1240 eV nmhc \approx 1240 \text{ eV nm} and converting the given energy to eV (15 keV=15,000 eV15 \text{ keV} = 15,000 \text{ eV}): λ=1240 eV nm15000 eV0.083 nm\lambda = \frac{1240 \text{ eV nm}}{15000 \text{ eV}} \approx 0.083 \text{ nm} According to the electromagnetic spectrum, X-rays have a wavelength range typically from 1 nm1 \text{ nm} to 103 nm10^{-3} \text{ nm} . Since 0.083 nm0.083 \text{ nm} falls within this range, the electromagnetic wave belongs to the X-ray region. Gamma rays typically have wavelengths less than 103 nm10^{-3} \text{ nm} (energies >100 keV> 100 \text{ keV}), while UV rays are in the range 400 nm400 \text{ nm} to 1 nm1 \text{ nm}.

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