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NEET PHYSICSMedium

A particle covers half of its total distance with speed v₁ and the rest half distance with speed v₂. Its average speed during the complete journey is

A

v₁v₂ / (v₁ + v₂)

B

2v₁v₂ / (v₁ + v₂)

C

2v₁²v₂² / (v₁² + v₂²)

D

(v₁ + v₂) / 2

Step-by-Step Solution

Average speed is defined as the total path length travelled divided by the total time interval during which the motion has taken place .

  1. Identify Parameters: Let the total distance be dd. Distance covered in the first half = d/2d/2 with speed v1v_1.
  • Distance covered in the second half = d/2d/2 with speed v2v_2.
  1. Calculate Time Taken: Time for the first half, t1=DistanceSpeed=d/2v1=d2v1t_1 = \frac{\text{Distance}}{\text{Speed}} = \frac{d/2}{v_1} = \frac{d}{2v_1}. Time for the second half, t2=d/2v2=d2v2t_2 = \frac{d/2}{v_2} = \frac{d}{2v_2}.
  • Total time, T=t1+t2=d2v1+d2v2=d2(1v1+1v2)=d2(v1+v2v1v2)T = t_1 + t_2 = \frac{d}{2v_1} + \frac{d}{2v_2} = \frac{d}{2} \left( \frac{1}{v_1} + \frac{1}{v_2} \right) = \frac{d}{2} \left( \frac{v_1 + v_2}{v_1 v_2} \right).
  1. Calculate Average Speed (vavgv_{avg}): vavg=Total DistanceTotal Timev_{avg} = \frac{\text{Total Distance}}{\text{Total Time}} vavg=dd(v1+v2)2v1v2v_{avg} = \frac{d}{\frac{d(v_1 + v_2)}{2v_1 v_2}} vavg=2v1v2v1+v2v_{avg} = \frac{2v_1 v_2}{v_1 + v_2} This result represents the harmonic mean of the individual speeds when equal distances are covered.
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