Back to Directory
NEET PHYSICSEasy

The electric and the magnetic field, associated with an electromagnetic wave, propagating along the +z+z-axis, can be represented by:

A

[E=E0k^,B=B0i^]\left[ \mathbf{E} = E_0 \hat{k}, \mathbf{B} = B_0 \hat{i} \right]

B

[E=E0j^,B=B0j^]\left[ \mathbf{E} = E_0 \hat{j}, \mathbf{B} = B_0 \hat{j} \right]

C

[E=E0j^,B=B0k^]\left[ \mathbf{E} = E_0 \hat{j}, \mathbf{B} = B_0 \hat{k} \right]

D

[E=E0i^,B=B0j^]\left[ \mathbf{E} = E_0 \hat{i}, \mathbf{B} = B_0 \hat{j} \right]

Step-by-Step Solution

Electromagnetic waves are transverse in nature, meaning the electric field (E\mathbf{E}), magnetic field (B\mathbf{B}), and the direction of propagation are mutually perpendicular. The direction of wave propagation is given by the direction of the vector cross product E×B\mathbf{E} \times \mathbf{B} .

Given that the wave propagates along the +z+z-axis (represented by unit vector k^\hat{k}), we must satisfy the condition: Direction of (E×B)=k^(\mathbf{E} \times \mathbf{B}) = \hat{k}.

Let's test the options:

  1. k^×i^=j^\hat{k} \times \hat{i} = \hat{j} (Propagates along yy-axis). Also, E\mathbf{E} cannot be along the direction of propagation.
  2. j^×j^=0\hat{j} \times \hat{j} = 0 (Fields cannot be parallel).
  3. j^×k^=i^\hat{j} \times \hat{k} = \hat{i} (Propagates along xx-axis).
  4. i^×j^=k^\hat{i} \times \hat{j} = \hat{k} (Propagates along zz-axis). This matches the given condition.
Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started
Solved: PHYSICS Question for NEET | Sushrut