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NEET PHYSICSEasy

The work functions of Caesium (Cs), Potassium (K) and Sodium (Na) are 2.14 eV, 2.30 eV and 2.75 eV respectively. If incident electromagnetic radiation has an incident energy of 2.20 eV, which of these photosensitive surfaces may emit photoelectrons?

A

Cs only

B

Both Na and K

C

K only

D

Na only

Step-by-Step Solution

Photoelectric emission occurs only if the incident energy EE is greater than or equal to the work function ϕ\phi of the metal. Given E=2.20E = 2.20 eV. For Cs, ϕ=2.14\phi = 2.14 eV. Since 2.20>2.142.20 > 2.14, Cs will emit photoelectrons. For K, ϕ=2.30\phi = 2.30 eV and for Na, ϕ=2.75\phi = 2.75 eV. Since 2.20<2.302.20 < 2.30 and 2.20<2.752.20 < 2.75, neither K nor Na will emit photoelectrons.

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