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NEET PHYSICSEasy

During simple harmonic motion of a body, the energy at the extreme position is:

A

both kinetic and potential

B

is always zero

C

purely kinetic

D

purely potential

Step-by-Step Solution

  1. Velocity at Extreme Position: In Simple Harmonic Motion (SHM), the particle oscillates between two extreme positions (±A±A) relative to a mean position (x=0x=0). At the extreme positions, the particle comes to a momentary rest, meaning its velocity (vv) is zero.
  2. Kinetic Energy: Since Kinetic Energy K=12mv2K = \frac{1}{2}mv^2, and v=0v=0 at the extremes, the kinetic energy is zero.
  3. Potential Energy: The displacement (xx) is maximum (x=±Ax = ±A) at the extreme positions. The Potential Energy (UU) is given by U=12kx2U = \frac{1}{2}kx^2. Therefore, potential energy is maximum at the extremes (Umax=12kA2U_{max} = \frac{1}{2}kA^2).
  4. Conservation of Energy: The Total Energy (EE) in SHM is the sum of kinetic and potential energies (E=K+UE = K + U). Since K=0K=0 at the extremes, the total energy is equal to the potential energy (E=UmaxE = U_{max}). Thus, the energy is purely potential .
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