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NEET PHYSICSEasy

A convex lens and a concave lens, each having the same focal length of 25 cm25\text{ cm}, are put in contact to form a combination of lenses. The power in dioptres of the combination is:

A

25

B

50

C

infinite

D

zero

Step-by-Step Solution

  1. Focal Lengths with Sign Convention: The focal length of a convex lens is positive, so f1=+25 cm=+0.25 mf_1 = +25\text{ cm} = +0.25\text{ m}. The focal length of a concave lens is negative, so f2=25 cm=0.25 mf_2 = -25\text{ cm} = -0.25\text{ m}.
  2. Power of Individual Lenses: The power PP of a lens in dioptres (D) is the reciprocal of its focal length in meters. Power of convex lens, P1=1+0.25=+4 DP_1 = \frac{1}{+0.25} = +4\text{ D}. Power of concave lens, P2=10.25=4 DP_2 = \frac{1}{-0.25} = -4\text{ D}.
  3. Power of Combination: When two thin lenses are placed in contact, the equivalent power of the combination is the algebraic sum of their individual powers.
  • Peq=P1+P2=+4 D+(4 D)=0 DP_{eq} = P_1 + P_2 = +4\text{ D} + (-4\text{ D}) = 0\text{ D}.
  1. Conclusion: The power of the lens combination is zero.
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