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A capillary tube of radius r is immersed in water and water rises in it to a height h. The mass of the water in the capillary is 5 g. Another capillary tube of radius 2r is immersed in water. The mass of water that will rise in this tube is :

A

2.5 g

B

5.0 g

C

10.0 g

D

20.0 g

Step-by-Step Solution

Force of surface tension balances the weight of water in capillary tube. Fs=2πrTcos⁡θ=mgF_s = 2\pi r T \cos\theta = mg. Here, TT and θ\theta are constant. So, m∝rm \propto r. Hence, m25.0=2rr⇒m2=10.0 g\frac{m_2}{5.0} = \frac{2r}{r} \Rightarrow m_2 = 10.0 \text{ g}.

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