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NEET PHYSICSEasy

Henry/ohm can be expressed in:

A

Second

B

Coulomb

C

Mho

D

Metre

Step-by-Step Solution

Identify the Physical Quantities: 'Henry' ( $H$ ) is the SI unit of Inductance ( $L$ ), and 'Ohm' ( $\Omega$ ) is the SI unit of Resistance ( $R$ ).
Dimensional Analysis:

The induced emf is given by $|\varepsilon| = L \frac{dI}{dt}$ , which implies $L = \frac{\varepsilon dt}{dI}$ . Thus, the unit Henry corresponds to $\frac{\text{Volt} \cdot \text{Second}}{\text{Ampere}}$ .
According to Ohm's Law, $V = IR$ , so the unit Ohm corresponds to $\frac{\text{Volt}}{\text{Ampere}}$ .

Calculate the Ratio: $\frac{\text{Henry}}{\text{Ohm}} = \frac{\frac{\text{Volt} \cdot \text{Second}}{\text{Ampere}}}{\frac{\text{Volt}}{\text{Ampere}}} = \text{Second}$
Alternative Method (Time Constant): The quantity $\tau = L/R$ represents the time constant of an LR circuit, which has the dimensions of time ( $[T]$ ), measured in seconds , .

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Solved: PHYSICS Question for NEET | Sushrut