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NEET PHYSICSMedium

A wire of length LL and radius rr (rLr \ll L) is kept floating on the surface of a liquid of density ρ\rho. The maximum radius of the wire for which it may not sink is: (the surface tension of liquid is TT)

A

Tρg\sqrt{\frac{T}{\rho g}}

B

2Tρg\sqrt{\frac{2T}{\rho g}}

C

2Tρπg\sqrt{\frac{2T}{\rho \pi g}}

D

2Tπρg\sqrt{\frac{2T}{\pi \rho g}}

Step-by-Step Solution

For the wire to float on the liquid surface without sinking, the upward force due to surface tension must balance the downward force due to the weight of the wire.

  1. Upward Force (FSTF_{ST}): Surface tension acts along the two lengths of the wire in contact with the surface. FST=T×2LF_{ST} = T \times 2L

  2. Downward Force (WW): This is the weight of the wire. W=mg=(Volume×Density)×gW = mg = (\text{Volume} \times \text{Density}) \times g W=(πr2L)×ρ×gW = (\pi r^2 L) \times \rho \times g (Note: In this context, ρ\rho represents the density of the wire for the weight equation. If the text specifies liquid density, it is likely assuming the wire density is comparable or ρ\rho refers to the object's density in the standard formula derivation).

  3. Equilibrium Condition: For the maximum radius before sinking, the forces are balanced: FST=WF_{ST} = W 2TL=πr2Lρg2TL = \pi r^2 L \rho g

  4. Solve for rr: 2T=πr2ρg2T = \pi r^2 \rho g r2=2Tπρgr^2 = \frac{2T}{\pi \rho g} r=2Tπρgr = \sqrt{\frac{2T}{\pi \rho g}}

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