Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

A missile is fired for maximum range with an initial velocity of $20 \text{ m/s}$ . If $g=10 \text{ m/s}^2$ , the range of the missile is:

50 m

60 m

20 m

40 m

Formula: The horizontal range $R$ of a projectile is given by $R = \frac{v_0^2 \sin 2\theta}{g}$ . For the range to be maximum, the angle of projection must be $\theta = 45^\circ$ , making $\sin 2\theta = 1$ .
Maximum Range Formula: The expression simplifies to $R_{\text{max}} = \frac{v_0^2}{g}$ .
Calculation: Given initial velocity $v_0 = 20 \text{ m/s}$ and acceleration due to gravity $g = 10 \text{ m/s}^2$ : $R_{\text{max}} = \frac{(20)^2}{10} = \frac{400}{10} = 40 \text{ m}$

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