To determine the physical quantity corresponding to the unit Joule-second ($J \cdot s$), we analyze the dimensions:

1. Joule (J): SI unit of Work or Energy. Dimensional formula is $[ML^2T^{-2}]$ .
2. Second (s): SI unit of Time. Dimensional formula is $[T]$.
3. Joule-second ($J \cdot s$): Multiply the dimensions: $[ML^2T^{-2}] \times [T] = [ML^2T^{-1}]$.
4. Compare with Options:

• Work: $[ML^2T^{-2}]$ (Unit: J). Mismatch.
• Momentum (Linear): $[MLT^{-1}]$ (Unit: $kg \cdot m \cdot s^{-1}$ or $N \cdot s$). Mismatch.
• Pressure: $[ML^{-1}T^{-2}]$ (Unit: $Pa$ or $N \cdot m^{-2}$). Mismatch.
• Angular Momentum: Formula is moment of momentum ($r \times p$). Dimensions are $[L] \times [MLT^{-1}] = [ML^2T^{-1}]$. This matches the dimensions of $J \cdot s$.
• Note: The unit $J \cdot s$ is also the unit of Planck's constant ($h$), which has the same dimensions as angular momentum .