Solved: PHYSICS Question for NEET | Sushrut

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NEET PHYSICSEasy

In the following circuit, the equivalent capacitance between terminal A and terminal B is:

A

1 \mu F

B

0.5 \mu F

C

4 \mu F

D

2 \mu F

Step-by-Step Solution

Missing Diagram: The problem requires a specific circuit diagram to identify the arrangement (series, parallel, or mixed) of the capacitors. This image is not provided in the input text.
General Principles:

Parallel Combination: For capacitors connected in parallel, the equivalent capacitance is the sum of individual capacitances: $C_{eq} = C_1 + C_2 + \dots$ .
Series Combination: For capacitors connected in series, the reciprocal of the equivalent capacitance is the sum of the reciprocals: $\frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2} + \dots$ .

Result: Accepting the probable answer of $2 \text{ \mu F}$ , the circuit likely contains a specific combination of capacitors that simplifies to this value.

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Solved: PHYSICS Question for NEET | Sushrut