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NEET PHYSICSMedium

If F\vec{F} is the force acting on a particle having position vector r\vec{r} and τ\vec{\tau} be the torque of this force about the origin, then:

A

rτ0\vec{r} \cdot \vec{\tau} \neq 0 and Fτ=0\vec{F} \cdot \vec{\tau} = 0

B

rτ>0\vec{r} \cdot \vec{\tau} > 0 and Fτ<0\vec{F} \cdot \vec{\tau} < 0

C

rτ=0\vec{r} \cdot \vec{\tau} = 0 and Fτ=0\vec{F} \cdot \vec{\tau} = 0

D

rτ=0\vec{r} \cdot \vec{\tau} = 0 and Fτ0\vec{F} \cdot \vec{\tau} \neq 0

Step-by-Step Solution

Torque is mathematically defined as the cross product of the position vector (r\vec{r}) and the force vector (F\vec{F}), i.e., τ=r×F\vec{\tau} = \vec{r} \times \vec{F}. A fundamental property of the cross product is that the resulting vector (τ\vec{\tau}) is always perpendicular (orthogonal) to the plane containing both r\vec{r} and F\vec{F}. Consequently, τ\vec{\tau} is perpendicular to r\vec{r} and also perpendicular to F\vec{F}. Since the dot product of any two perpendicular vectors is zero, we must have rτ=0\vec{r} \cdot \vec{\tau} = 0 and Fτ=0\vec{F} \cdot \vec{\tau} = 0.

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