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NEET PHYSICSEasy

A person of mass 60 kg60 \text{ kg} is inside a lift of mass 940 kg940 \text{ kg} and presses the button on the control panel. The lift starts moving upwards with an acceleration of 1.0 m/s21.0 \text{ m/s}^2. If g=10 m/s2g=10 \text{ m/s}^2, the tension in the supporting cable is:

A

9680 N9680 \text{ N}

B

11000 N11000 \text{ N}

C

1200 N1200 \text{ N}

D

8600 N8600 \text{ N}

Step-by-Step Solution

  1. System Analysis: Consider the lift and the person together as a single system. The total mass MM is the sum of the mass of the lift and the mass of the person. M=940 kg+60 kg=1000 kgM = 940 \text{ kg} + 60 \text{ kg} = 1000 \text{ kg}
  2. Forces Involved:
  • The tension TT in the supporting cable acts vertically upwards.
  • The total weight of the system (MgMg) acts vertically downwards.
  1. Equation of Motion: Since the lift is accelerating upwards with acceleration a=1.0 m/s2a = 1.0 \text{ m/s}^2, we apply Newton's Second Law (Fnet=MaF_{net} = Ma) [NCERT Class 11, Physics Part I, Laws of Motion, Section 5.5]: TMg=MaT - Mg = Ma T=M(g+a)T = M(g + a)
  2. Calculation: Substitute the values (M=1000M=1000, g=10g=10, a=1a=1): T=1000×(10+1.0)T = 1000 \times (10 + 1.0) T=1000×11=11000 NT = 1000 \times 11 = 11000 \text{ N}
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