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NEET PHYSICSEasy

Two identical balls A and B having velocities of 0.5 m/s0.5 \text{ m/s} and 0.3 m/s-0.3 \text{ m/s} respectively collide elastically in one dimension. The velocities of B and A after the collision respectively will be:

A

0.5 m/s-0.5 \text{ m/s} and 0.3 m/s0.3 \text{ m/s}

B

0.5 m/s0.5 \text{ m/s} and 0.3 m/s-0.3 \text{ m/s}

C

0.3 m/s-0.3 \text{ m/s} and 0.5 m/s0.5 \text{ m/s}

D

0.3 m/s0.3 \text{ m/s} and 0.5 m/s0.5 \text{ m/s}

Step-by-Step Solution

In a perfectly elastic one-dimensional collision between two bodies of equal mass, the bodies exchange their velocities. Given that the masses are identical (mA=mBm_A = m_B) and the initial velocities are uA=0.5 m/su_A = 0.5 \text{ m/s} and uB=0.3 m/su_B = -0.3 \text{ m/s}. After the collision, their final velocities will be vA=uB=0.3 m/sv_A = u_B = -0.3 \text{ m/s} and vB=uA=0.5 m/sv_B = u_A = 0.5 \text{ m/s}. The question asks for the velocities of B and A respectively, so the order is vBv_B then vAv_A, which is 0.5 m/s0.5 \text{ m/s} and 0.3 m/s-0.3 \text{ m/s}.

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