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NEET PHYSICSEasy

The molecular weight of two gases is M1M_1 and M2M_2. At any temperature, the ratio of root mean square velocities v1v_1 and v2v_2 will be:

A

M1M2\sqrt{\frac{M_1}{M_2}}

B

M2M1\sqrt{\frac{M_2}{M_1}}

C

M1+M2M1M2\sqrt{\frac{M_1+M_2}{M_1-M_2}}

D

M1M2M1+M2\sqrt{\frac{M_1-M_2}{M_1+M_2}}

Step-by-Step Solution

The root mean square velocity (vrmsv_{rms}) of a gas molecule is given by the formula vrms=3RTMv_{rms} = \sqrt{\frac{3RT}{M}} (or thermal speed vkBTMv \approx \sqrt{\frac{k_B T}{M}}) . At a constant temperature (TT), the velocity is inversely proportional to the square root of the molecular weight (MM): vrms1Mv_{rms} \propto \frac{1}{\sqrt{M}}. Therefore, the ratio of the velocities is: v1v2=1M11M2=M2M1\frac{v_1}{v_2} = \frac{\sqrt{\frac{1}{M_1}}}{\sqrt{\frac{1}{M_2}}} = \sqrt{\frac{M_2}{M_1}}.

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