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NEET PHYSICSMedium

The effective resistance of a parallel connection that consists of four wires of equal length, equal area of cross-section and same material is 0.25 Ω0.25 \ \Omega. What will be the effective resistance if they are connected in series?

A

0.25 Ω0.25 \ \Omega

B

0.5 Ω0.5 \ \Omega

C

1 Ω1 \ \Omega

D

4 Ω4 \ \Omega

Step-by-Step Solution

All the wires are identical and of same material so they will have same value of resistance. Let it be RR. When these are (four) connected in parallel, Rp=R/4R_p = R/4. Given Rp=0.25 ΩR_p = 0.25 \ \Omega, so 0.25=R/40.25 = R/4, which gives R=1 ΩR = 1 \ \Omega. Now these four resistances are arranged in series, Rs=R+R+R+R=4RR_s = R + R + R + R = 4R. Therefore, Rs=4×1=4 ΩR_s = 4 \times 1 = 4 \ \Omega.

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