Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

Two bodies of mass $4 \text{ kg}$ and $6 \text{ kg}$ are tied to the ends of a massless string. The string passes over a pulley, which is frictionless (see figure). The acceleration of the system in terms of acceleration due to gravity ( $g$ ) is:

$\frac{g}{2}$

$\frac{g}{5}$

$\frac{g}{10}$

$g$

Step-by-Step Solution

Identify the System: This setup describes an Atwood Machine, where two masses are suspended over a frictionless pulley via a massless inextensible string.
Forces Involved: The heavier mass ( $m_2 = 6 \text{ kg}$ ) accelerates downwards, while the lighter mass ( $m_1 = 4 \text{ kg}$ ) accelerates upwards. The driving force is the difference in their weights.
Apply Newton's Second Law: $a = \frac{\text{Net Force}}{\text{Total Mass}} = \frac{(m_2 - m_1)g}{m_1 + m_2}$
Calculation: Substitute the given values: $a = \frac{(6 - 4)g}{6 + 4} = \frac{2g}{10} = \frac{g}{5}$ (Reference: NCERT Class 11, Physics Part I, Chapter 5: Laws of Motion, application of Newton's laws to connected bodies).

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