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NEET PHYSICSMedium

The total energy of an electron in an atom in an orbit is 3.4 eV-3.4 \text{ eV}. Its kinetic and potential energies are, respectively:

1

3.4 eV,3.4 eV-3.4 \text{ eV}, -3.4 \text{ eV}

2

3.4 eV,6.8 eV-3.4 \text{ eV}, -6.8 \text{ eV}

3

3.4 eV,6.8 eV3.4 \text{ eV}, -6.8 \text{ eV}

4

3.4 eV,3.4 eV3.4 \text{ eV}, 3.4 \text{ eV}

Step-by-Step Solution

In Bohr's model of H atom, K.E.=TE=U2\text{K.E.} = |\text{TE}| = \frac{|\text{U}|}{2}. Therefore, K.E.=3.4 eV\text{K.E.} = 3.4 \text{ eV} and U=6.8 eV\text{U} = -6.8 \text{ eV}.

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