Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

Find the maximum velocity for skidding for a car moving on a circular track of radius 100 m. The coefficient of friction between the road and tyre is 0.2.

0.14 m/s

140 m/s

1.4 km/s

14 m/s

Step-by-Step Solution

Identify the Principle: For a car moving on a level circular track, the necessary centripetal force is provided by the force of static friction between the tyres and the road [Source 69].
Formula: The maximum safe speed ( $v_{max}$ ) to avoid skidding is given by the condition where the maximum static friction equals the centripetal force: $\frac{mv_{max}^2}{R} = \mu_s mg$ $v_{max} = \sqrt{\mu_s Rg}$ [Source 69, 70]
Calculation:

Coefficient of friction ( $\mu_s$ ) = 0.2
Radius ( $R$ ) = 100 m
Acceleration due to gravity ( $g$ ) $\approx 9.8 \text{ m/s}^2$ Substitute the values: $v_{max} = \sqrt{0.2 \times 100 \times 9.8}$ $v_{max} = \sqrt{196}$ $v_{max} = 14 \text{ m/s}$

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