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NEET PhysicsEasy

The mean free path for a gas, with molecular diameter d and number density n can be expressed as :

1

12nπd\frac{1}{\sqrt{2} n \pi d}

2

12nπd2\frac{1}{\sqrt{2} n \pi d^2}

3

12n2πd2\frac{1}{\sqrt{2} n^2 \pi d^2}

4

12n2π2d2\frac{1}{\sqrt{2} n^2 \pi^2 d^2}

Step-by-Step Solution

According to the kinetic theory of gases, the mean free path λ=12nπd2\lambda = \frac{1}{\sqrt{2} n \pi d^2}.

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