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NEET PHYSICSEasy

A block of mass 4 kg is suspended through two light spring balances A and B connected in series. Then A and B will read respectively:

A

4 kg and 0 kg

B

0 kg and 4 kg

C

4 kg and 4 kg

D

2 kg and 2 kg

Step-by-Step Solution

  1. System Configuration: When two light (massless) spring balances are connected in series (one suspended from the other) supporting a mass, the tension is uniform throughout the chain.
  2. Free Body Diagram:
  • For the block: The downward force is weight W=mg=4gW = mg = 4g. The upward force is the tension in Balance B (TBT_B). For equilibrium, TB=4gT_B = 4g. Balance B reads 44 kg.
  • For Balance B: It is massless. It is pulled down by tension TBT_B and pulled up by tension from Balance A (TAT_A). For equilibrium, TA=TB=4gT_A = T_B = 4g. Balance A reads 44 kg [Source 41].
  1. Newton's Third Law: The action and reaction forces are equal and opposite. The force transmitted through the series of massless springs is equal to the load suspended.
  2. Conclusion: Both spring balances measure the same tension corresponding to the mass of the block.
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Solved: PHYSICS Question for NEET | Sushrut