Solved: Physics Question for NEET

NEET PhysicsMedium

A ball is thrown vertically downward with a velocity of $20 \text{ m/s}$ from the top of a tower. It hits the ground after some time with a velocity of $80 \text{ m/s}$ . The height of the tower is : ( $g = 10 \text{ m/s}^2$ )

360 \text{ m}

340 \text{ m}

320 \text{ m}

300 \text{ m}

Step-by-Step Solution

$v^2 = u^2 + 2gh$ . $v = 80 \text{ m/s}$ , $u = 20 \text{ m/s}$ . $h = \frac{v^2 - u^2}{2g} = \frac{6400 - 400}{20} = 300 \text{ m}$ .

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started