Solved: PHYSICS Question for NEET

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The dimensional formula for Young's modulus is

$[ML^{-1}T^{-2}]$

$[M^0LT^{-2}]$

$[MLT^{-2}]$

$[ML^2T^{-2}]$

Definition: Young's modulus ( $Y$ ) is defined as the ratio of tensile (or compressive) stress to longitudinal strain . $Y = \frac{\text{Stress}}{\text{Strain}}$
Identify Dimensions:

Stress: Force per unit area, so its dimensional formula is $\frac{[MLT^{-2}]}{[L^2]} = [ML^{-1}T^{-2}]$ .
Strain: Ratio of change in length to original length, so it is a dimensionless quantity $[M^0L^0T^0]$ .

Calculate Final Dimensions: $[Y] = \frac{[ML^{-1}T^{-2}]}{[M^0L^0T^0]} = [ML^{-1}T^{-2}]$ .

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