Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

A point charge causes an electric flux of $-1.0 \times 10^3$ Nm $^2$ /C to pass through a spherical Gaussian surface of 10.0 cm radius centered on the charge. If the radius of the Gaussian surface were doubled, how much flux would pass through the surface?

$-2.0 \times 10^3$ Nm $^2$ /C

$-1.0 \times 10^3$ Nm $^2$ /C

$2.0 \times 10^3$ Nm $^2$ /C

Zero

Step-by-Step Solution

According to Gauss's Law, the total electric flux $\Phi_E$ through a closed surface is equal to $\frac{q}{\varepsilon_0}$ , where $q$ is the net charge enclosed by the surface. The flux depends only on the amount of enclosed charge and is independent of the size or shape of the Gaussian surface. Therefore, doubling the radius of the spherical surface does not change the amount of charge enclosed, and the electric flux remains the same. (See NCERT Physics Class 12, Exercise 1.19).

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