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NEET PHYSICSEasy

If ∮sE⃗⋅dS⃗=0\oint_s \vec{E} \cdot d\vec{S} = 0 over a surface, then

A

The number of flux lines entering the surface must be equal to the number of flux lines leaving it

B

The magnitude of electric field on the surface is constant

C

All the charges must necessarily be inside the surface

D

The electric field inside the surface is necessarily uniform

Step-by-Step Solution

Gauss's Law states that the total electric flux ∮E⃗⋅dS⃗=qenclosedϵ0\oint \vec{E} \cdot d\vec{S} = \frac{q_{enclosed}}{\epsilon_0}. If the integral is zero, the net charge enclosed is zero. This means the net flux is zero, implying the number of field lines entering equals the number leaving.

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