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NEET PHYSICSEasy

A body of mass 5 kg is moving in a circle of radius 1 m with an angular velocity of 2 rad/s. The centripetal force is:

A

10 N

B

20 N

C

30 N

D

40 N

Step-by-Step Solution

  1. Identify Given Values:
  • Mass (mm) = 5 kg
  • Radius (RR) = 1 m
  • Angular velocity (ω\omega) = 2 rad/s
  1. Formula Selection: The centripetal force (FcF_c) required to keep a body moving in a circular path with angular velocity is given by Newton's Second Law applied to centripetal acceleration (ac=ω2Ra_c = \omega^2 R): Fc=mac=mω2RF_c = m a_c = m \omega^2 R [Source 43, 63]

  2. Calculation: Substitute the given values into the equation: Fc=5 kg×(2 rad/s)2×1 mF_c = 5 \text{ kg} \times (2 \text{ rad/s})^2 \times 1 \text{ m} Fc=5×4×1F_c = 5 \times 4 \times 1 Fc=20 NF_c = 20 \text{ N}

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