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NEET PHYSICSMedium

A person can see objects clearly only when they lie between 50 cm and 400 cm from his eyes. In order to increase the maximum distance of distinct vision to infinity, the type and power of the correcting lens, the person has to use, will be:

A

convex, +2.25 D

B

concave, -0.25 D

C

concave, -0.2 D

D

convex, +0.5 D

Step-by-Step Solution

The person's far point is 400 cm, which means they cannot see clearly beyond this distance. This condition is known as Myopia or Nearsightedness.

  1. Type of Lens: To correct myopia, a concave lens is used to diverge incoming parallel rays from infinity so that they appear to diverge from the person's actual far point.
  2. Calculation: Object distance (uu) = \infty (since we want to see objects at infinity). Image distance (vv) = Distance of the person's far point = 400-400 cm (virtual image formed in front of the eye). Using the lens formula: 1f=1v1u\frac{1}{f} = \frac{1}{v} - \frac{1}{u} 1f=14001=1400\frac{1}{f} = \frac{1}{-400} - \frac{1}{-\infty} = -\frac{1}{400} Focal length (ff) = 400-400 cm = 4-4 m. Power (PP) = 1f (in meters)=14=0.25\frac{1}{f \text{ (in meters)}} = \frac{1}{-4} = -0.25 Diopter (D).

Thus, the required lens is concave with a power of 0.25-0.25 D.

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