The efficiency of a Carnot engine is given by the formula: $\eta = 1 - \frac{T_2}{T_1}$ Where $T_1$ is the temperature of the source in Kelvin and $T_2$ is the temperature of the sink in Kelvin. Given, $\eta = 50\% = 0.5$ $T_1 = 327^\circ \mathrm{C} = 327 + 273 = 600 \text{ K}$ Substituting the values: $0.5 = 1 - \frac{T_2}{600}$ $\frac{T_2}{600} = 0.5 \implies T_2 = 300 \text{ K}$ Converting the sink temperature back to Celsius: $T_2 = 300 - 273 = 27^\circ \mathrm{C}$