The circuit consists of two capacitors in series with a third capacitor in parallel, or a bridge configuration. Looking at the diagram, the two $3 \mu F$ capacitors are in series, giving $C_{series} = \frac{3 \times 3}{3 + 3} = 1.5 \mu F$. This is then in parallel with the other $3 \mu F$ capacitor? No, looking at the diagram, it is a bridge. The two $3 \mu F$ capacitors on the right are in series ($1.5 \mu F$), and the $3 \mu F$ on the left is in parallel with that combination. Wait, the diagram shows a standard bridge. If balanced, the middle is ignored. Here, $3/3 = 3/3$, so it is balanced. The equivalent is $(3+3)$ in series with $(3+3)$, which is $6/2 = 3 \mu F$. Re-evaluating: The diagram shows two $3 \mu F$ in series, and that branch is in parallel with the other $3 \mu F$. Actually, the simplest interpretation of the visual is $C_{eq} = 3 \mu F || (3 \mu F + 3 \mu F) = 3 || 1.5 = 2 \mu F$.