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NEET PHYSICSMedium

A 220V input is supplied to a transformer. The output circuit draws a current of 2.0A at 440V. If the efficiency of the transformer is 80%, the current drawn by the primary windings of the transformer is

A

3.6A

B

2.8A

C

2.5A

D

5.0A

Step-by-Step Solution

The efficiency (η\eta) of a transformer is defined as the ratio of output power (PoutP_{out}) to input power (PinP_{in}). Formula: η=PoutPin=VsIsVpIp\eta = \frac{P_{out}}{P_{in}} = \frac{V_s I_s}{V_p I_p} . Given: Input Voltage (VpV_p) = 220 V Output Voltage (VsV_s) = 440 V Output Current (IsI_s) = 2.0 A Efficiency (η\eta) = 80% = 0.8

Calculation:

  1. Calculate Output Power: Pout=VsIs=440 V×2.0 A=880 WP_{out} = V_s I_s = 440 \text{ V} \times 2.0 \text{ A} = 880 \text{ W}.
  2. Calculate Input Power: Pin=Poutη=8800.8=1100 WP_{in} = \frac{P_{out}}{\eta} = \frac{880}{0.8} = 1100 \text{ W}.
  3. Calculate Primary Current: Since Pin=VpIpP_{in} = V_p I_p, then Ip=PinVp=1100220=5.0 AI_p = \frac{P_{in}}{V_p} = \frac{1100}{220} = 5.0 \text{ A}.
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