Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

The ratio of the distances travelled by a freely falling body in the 1st, 2nd, 3rd and 4th second is:

1:1:1:1

1:2:3:4

1:4:9:16

1:3:5:7

Identify the Law: The distance traversed by a body falling from rest during equal intervals of time follows Galileo's Law of Odd Numbers .
Mathematical Relation: The distance ( $S_n$ ) travelled in the $n$ -th second of uniformly accelerated motion (starting from rest, $u=0$ ) is given by: $S_n = \frac{g}{2}(2n - 1)$ This shows that $S_n \propto (2n - 1)$ .
Calculate Ratios: For $n=1$ (1st second): $S_1 \propto (2(1) - 1) = 1$ For $n=2$ (2nd second): $S_2 \propto (2(2) - 1) = 3$ For $n=3$ (3rd second): $S_3 \propto (2(3) - 1) = 5$ For $n=4$ (4th second): $S_4 \propto (2(4) - 1) = 7$
Conclusion: The ratio of distances is $1:3:5:7$ .

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