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NEET PHYSICSEasy

A square loop of side 1 m1\text{ m} and resistance 1 Ω1\text{ }\Omega is placed in a magnetic field of 0.5 T0.5\text{ T}. If the plane of loop is perpendicular to the direction of magnetic field, the magnetic flux through the loop is

A

2 weber2\text{ weber}

B

0.5 weber0.5\text{ weber}

C

1 weber1\text{ weber}

D

Zero weber

Step-by-Step Solution

Magnetic flux ϕB=B⃗⋅A⃗\phi_B = \vec{B} \cdot \vec{A}. Since B⃗\vec{B} and A⃗\vec{A} are in the same direction, ϕB=B⋅A=0.5×(1)2=0.5 Wb\phi_B = B \cdot A = 0.5 \times (1)^2 = 0.5\text{ Wb}.

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