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NEET PHYSICSMedium

An ideal gas is compressed to half its initial volume using several processes. Which of the processes results in the maximum work done on the gas?

A

adiabatic

B

isobaric

C

isochoric

D

isothermal

Step-by-Step Solution

The work done on a gas during compression is given by the area under the pressure-volume (PVP-V) curve (w=PexdVw = -\int P_{ex} dV) .

  1. Isochoric Process: The volume is constant (dV=0dV = 0), so the work done is zero .
  2. Isobaric Process: The pressure is constant. The work done is the area of the rectangle under the horizontal line.
  3. Isothermal vs. Adiabatic: For an ideal gas, the slope of the adiabatic curve (PVγ=constantPV^\gamma = \text{constant}) is steeper than that of the isothermal curve (PV=constantPV = \text{constant}) because γ>1\gamma > 1. During compression from an initial volume VV to V/2V/2, the final pressure attained in an adiabatic process is higher than in an isothermal process (since temperature increases in adiabatic compression but remains constant in isothermal).
  • Consequently, the P-V curve for adiabatic compression lies above the isothermal curve, enclosing a larger area.

Therefore, the maximum work is done in the adiabatic compression.

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