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NEET PHYSICSEasy

The ratio of the moments of inertia of two spheres, about their diameters, having the same mass and their radii being in the ratio of 1:21:2, is:

A

2:12:1

B

4:14:1

C

1:21:2

D

1:41:4

Step-by-Step Solution

The moment of inertia of a sphere about its diameter is proportional to the product of its mass and the square of its radius (IMR2I \propto MR^2). Given that both spheres have the same mass (M1=M2=MM_1 = M_2 = M) and the ratio of their radii is R1:R2=1:2R_1 : R_2 = 1 : 2. The ratio of their moments of inertia will be: I1I2=M1R12M2R22=(R1R2)2\frac{I_1}{I_2} = \frac{M_1 R_1^2}{M_2 R_2^2} = \left(\frac{R_1}{R_2}\right)^2 I1I2=(12)2=14\frac{I_1}{I_2} = \left(\frac{1}{2}\right)^2 = \frac{1}{4} Therefore, the ratio is 1:41:4.

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