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If in a p-n junction, a square input signal of 10 V10 \text{ V} is applied as shown, then the output across RLR_L will be:

A

Square wave from +5 V+5 \text{ V} to 5 V-5 \text{ V}

B

Constant +5 V+5 \text{ V} DC

C

Square wave from 5 V-5 \text{ V} to 0 V0 \text{ V}

D

Square wave from 0 V0 \text{ V} to +5 V+5 \text{ V}

Step-by-Step Solution

Since the exact circuit diagram and input/output waveforms are missing from the text, this solution is based on the standard NEET 2015 question it refers to. The typical circuit involves a diode in series with a load resistor RLR_L acting as a half-wave rectifier. The input is a 10 V10 \text{ V} peak-to-peak square wave (ranging from 5 V-5 \text{ V} to +5 V+5 \text{ V}).

During the positive half-cycle (when the input is +5 V+5 \text{ V}), the p-n junction diode is forward-biased and conducts, dropping the entire +5 V+5 \text{ V} across the load resistor RLR_L (assuming an ideal diode). During the negative half-cycle (when the input is 5 V-5 \text{ V}), the diode is reverse-biased and acts as an open circuit, so no current flows and the voltage across RLR_L is 0 V0 \text{ V}. Therefore, the output waveform is a half-wave rectified square signal containing only the positive half-cycles (from 0 V0 \text{ V} to +5 V+5 \text{ V}).

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