Solved: PHYSICS Question for NEET

NEET PHYSICSMedium

A soap bubble, having radius of $1\text{ mm}$ , is blown from a detergent solution having a surface tension of $2.5 \times 10^{-2}\text{ N/m}$ . The pressure inside the bubble equals at a point $Z_0$ below the free surface of water in a container. Taking $g = 10\text{ m/s}^2$ , density of water $= 10^3\text{ kg/m}^3$ , the value of $Z_0$ is :

$100\text{ cm}$

$10\text{ cm}$

$1\text{ cm}$

$0.5\text{ cm}$

Step-by-Step Solution

Excess pressure $= \frac{4T}{R}$ , Gauge pressure $= \rho g Z_0$ . $P_0 + \frac{4T}{R} = P_0 + \rho g Z_0$ . $Z_0 = \frac{4T}{R \times \rho g} = \frac{4 \times 2.5 \times 10^{-2}}{10^{-3} \times 1000 \times 10}\text{ m} = 1\text{ cm}$ .

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