Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

Two bodies, A (of mass 1 kg) and B (of mass 3 kg) are dropped from heights of 16 m and 25 m, respectively. The ratio of the time taken by them to reach the ground is:

5/4

12/5

5/12

4/5

Step-by-Step Solution

Identify Kinematic Equation: For a body falling freely from rest ( $u = 0$ ) under gravity ( $a = g$ ), the distance fallen ( $h$ ) in time ( $t$ ) is given by the equation: $h = \frac{1}{2}gt^2$ Solving for time, we get: $t = \sqrt{\frac{2h}{g}}$ Note: The time of fall is independent of the mass of the body .
Calculate Time for Each Body: For body A ( $h_A = 16$ m): $t_A = \sqrt{\frac{2(16)}{g}}$ For body B ( $h_B = 25$ m): $t_B = \sqrt{\frac{2(25)}{g}}$
Calculate Ratio: $\frac{t_A}{t_B} = \frac{\sqrt{2(16)/g}}{\sqrt{2(25)/g}} = \sqrt{\frac{16}{25}} = \frac{4}{5}$

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