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NEET PHYSICSMedium

A particular station of All India Radio, New Delhi broadcasts on a frequency of 1,368 kHz (kilohertz). The wavelength of the electromagnetic radiation emitted by the transmitter is : [speed of light c=3.0×108 ms−1c = 3.0 \times 10^8 \text{ ms}^{-1}]

A

219.3 m

B

219.2 m

C

2192 m

D

21.92 cm

Step-by-Step Solution

Using the relation λ=cν\lambda = \frac{c}{\nu}, where c=3.0×108 m/sc = 3.0 \times 10^8 \text{ m/s} and ν=1368×103 Hz\nu = 1368 \times 10^3 \text{ Hz}. λ=3.0×1081368×103≈219.3 m\lambda = \frac{3.0 \times 10^8}{1368 \times 10^3} \approx 219.3 \text{ m}.

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