Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

In a U-tube, as shown in the figure, the water and oil are in the left side and right side of the tube respectively. The height of the water and oil columns are 15 cm and 20 cm respectively. The density of the oil is: [take \rho _water = 1000 kg/m^3]

1200 kg/m^3

750 kg/m^3

1000 kg/m^3

1333 kg/m^3

Step-by-Step Solution

Principle: According to Pascal's Law and the principles of hydrostatics, the pressure at the same horizontal level in a continuous liquid at rest is the same . In a U-tube, the pressure exerted by the liquid columns at the level of the interface must be equal.
Formula: The pressure exerted by a liquid column is given by $P = \rho g h$ , where $\rho$ is density, $g$ is acceleration due to gravity, and $h$ is the height of the column .
Calculation: Equating the pressure exerted by the water column to that of the oil column: $\rho_{water} g h_{water} = \rho_{oil} g h_{oil}$ $1000 \times g \times 15 = \rho_{oil} \times g \times 20$ Canceling $g$ from both sides: $15000 = 20 \rho_{oil}$ $\rho_{oil} = \frac{15000}{20} = 750 \text{ kg/m}^3$

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started