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NEET PHYSICSEasy

A transistor-oscillator using a resonant circuit with an inductance L (of negligible resistance) and a capacitance C has a frequency f. If L is doubled and C is changed to 4C, the frequency will be:

A

f/4

B

8f

C

f/2√2

D

f/2

Step-by-Step Solution

The frequency of oscillation of a resonant LC circuit is given by the formula f=12πLCf = \frac{1}{2\pi\sqrt{LC}} . Given the initial frequency f=12πLCf = \frac{1}{2\pi\sqrt{LC}}. New Inductance L=2LL' = 2L and new Capacitance C=4CC' = 4C. The new frequency ff' is given by: f=12πLC=12π(2L)(4C)=12π8LCf' = \frac{1}{2\pi\sqrt{L'C'}} = \frac{1}{2\pi\sqrt{(2L)(4C)}} = \frac{1}{2\pi\sqrt{8LC}} f=1812πLC=122ff' = \frac{1}{\sqrt{8}} \cdot \frac{1}{2\pi\sqrt{LC}} = \frac{1}{2\sqrt{2}} f.

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