Solved: PHYSICS Question for NEET | Sushrut

Back to Directory

NEET PHYSICSEasy

The equivalent capacitance of the system shown in the following circuit is:

A

9 \mu F

B

2 \mu F

C

3 \mu F

D

6 \mu F

Step-by-Step Solution

Missing Diagram: The problem requires a circuit diagram to determine the specific arrangement (series/parallel) of the capacitors.
General Principles:

Parallel Combination: Capacitors connected in parallel have an equivalent capacitance $C_p = C_1 + C_2 + \dots$ .
Series Combination: Capacitors connected in series have an equivalent capacitance given by $\frac{1}{C_s} = \frac{1}{C_1} + \frac{1}{C_2} + \dots$ .

Hypothetical Scenario: For an answer of $2 \text{ \mu F}$ , a common configuration in such exams involving $3 \text{ \mu F}$ capacitors is two capacitors in parallel ( $3+3=6 \text{ \mu F}$ ) connected in series with a third $3 \text{ \mu F}$ capacitor. The equivalent would be $\frac{6 \times 3}{6 + 3} = \frac{18}{9} = 2 \text{ \mu F}$ . Without the image, this is a likely theoretical derivation.

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Solved: PHYSICS Question for NEET | Sushrut